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9x^2-56x+80=0
a = 9; b = -56; c = +80;
Δ = b2-4ac
Δ = -562-4·9·80
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-16}{2*9}=\frac{40}{18} =2+2/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+16}{2*9}=\frac{72}{18} =4 $
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